What is the solution for y^'=((5x^3+y^3))/(xy^2) ?

The solution for y^'=((5x^3+y^3))/(xy^2) is y=x\sqrt[3]{15ln(x)+c_{1}}

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y^'=((5x^3+y^3))/(xy^2)

y^{^{'}} = \frac{( 5 x ^{3} + y ^{3} )}{x y ^{2}}

y = x 3 15 ln (x) + c_{1}

Solution steps

y^{'} (x) = \frac{( 5 x ^{3} + y ^{3} )}{x y ^{2}}

Solve Bernoulli ODE:

y = x 3 15 ln (x) + c_{1}

y = x 3 15 ln (x) + c_{1}

d er i v a t i v e f (x) = 6 x + 1

d er i v a t i v e r (x) = sin (x^{2}) + \frac{1 - x}{1 + x}

d er i v a t i v e 3 arctan (x - 1 + x^{2})

d er i v a t i v e o

\int (3 x^{2} - \frac{1}{x ^{2}}) d x

What is the solution for y^'=((5x^3+y^3))/(xy^2) ?
The solution for y^'=((5x^3+y^3))/(xy^2) is y=x\sqrt[3]{15ln(x)+c_{1}}