What is the derivative of (x^3+4x^7) ?

The derivative of (x^3+4x^7) is 7(x^3+4x)^6(3x^2+4)

What is the first derivative of (x^3+4x^7) ?

The first derivative of (x^3+4x^7) is 7(x^3+4x)^6(3x^2+4)

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\frac{d}{d x} ((x^{3} + 4 x)^{7})

7 (x^{3} + 4 x)^{6} (3 x^{2} + 4)

Solution steps

\frac{d}{d x} ((x^{3} + 4 x)^{7})

Apply the chain rule:

7 (x^{3} + 4 x)^{6} \frac{d}{d x} (x^{3} + 4 x)

= 7 (x^{3} + 4 x)^{6} \frac{d}{d x} (x^{3} + 4 x)

\frac{d}{d x} (x^{3} + 4 x) = 3 x^{2} + 4

= 7 (x^{3} + 4 x)^{6} (3 x^{2} + 4)

x \to 0 lim (3 x^{x})

\int \frac{( x - 1 )}{x} d x

d o main f (x) = (3 x^{2})^{2 x} (x^{2} + 2 x)^{2}

y^{^{''}} - 6 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 9

\frac{d y}{d t} = \frac{1}{5} t

What is the derivative of (x^3+4x^7) ?
The derivative of (x^3+4x^7) is 7(x^3+4x)^6(3x^2+4)
What is the first derivative of (x^3+4x^7) ?
The first derivative of (x^3+4x^7) is 7(x^3+4x)^6(3x^2+4)