What is the derivative of 1/(sqrt(x+6)) ?

The derivative of 1/(sqrt(x+6)) is -1/(2(x+6)^{3/2)}

What is the first derivative of 1/(sqrt(x+6)) ?

The first derivative of 1/(sqrt(x+6)) is -1/(2(x+6)^{3/2)}

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derivative of

\frac{1}{x + 6}

- \frac{1}{2 ( x + 6 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 6})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 6)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x + 6 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 6)

= - \frac{1}{2 ( x + 6 ) ^{\frac{3}{2}}} \frac{d}{d x} (x + 6)

\frac{d}{d x} (x + 6) = 1

= - \frac{1}{2 ( x + 6 ) ^{\frac{3}{2}}} \cdot 1

Simplify

= - \frac{1}{2 ( x + 6 ) ^{\frac{3}{2}}}

\int (- 2 x + 3) d x

3 x^{2} + 8

\int \frac{1}{v ^{2} - v} d v

f (θ) = 3 sin (θ)

\frac{\partial}{\partial y} (5 x y^{2} + x^{2})

What is the derivative of 1/(sqrt(x+6)) ?
The derivative of 1/(sqrt(x+6)) is -1/(2(x+6)^{3/2)}
What is the first derivative of 1/(sqrt(x+6)) ?
The first derivative of 1/(sqrt(x+6)) is -1/(2(x+6)^{3/2)}