What is the derivative of ln^2(1-2x) ?

The derivative of ln^2(1-2x) is -(4ln(1-2x))/(1-2x)

What is the first derivative of ln^2(1-2x) ?

The first derivative of ln^2(1-2x) is -(4ln(1-2x))/(1-2x)

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\frac{d}{d x} (ln^{2} (1 - 2 x))

- \frac{4 ln ( 1 - 2 x )}{1 - 2 x}

Solution steps

\frac{d}{d x} (ln^{2} (1 - 2 x))

Apply the chain rule:

2 ln (1 - 2 x) \frac{d}{d x} (ln (1 - 2 x))

= 2 ln (1 - 2 x) \frac{d}{d x} (ln (1 - 2 x))

\frac{d}{d x} (ln (1 - 2 x)) = - \frac{2}{1 - 2 x}

= 2 ln (1 - 2 x) (- \frac{2}{1 - 2 x})

Simplify

2 ln (1 - 2 x) (- \frac{2}{1 - 2 x}) : - \frac{4 ln ( 1 - 2 x )}{1 - 2 x}

= - \frac{4 ln ( 1 - 2 x )}{1 - 2 x}

f (x) = \frac{x}{ln ( x )}

y^{^{''}} + 6 y^{^{'}} + 19 y = 0

y^{^{''}} = 0

\int \frac{1}{25 + ( x - 6 ) ^{2}} d x

\frac{1}{5 s ^{2} + 0.2 s}

What is the derivative of ln^2(1-2x) ?
The derivative of ln^2(1-2x) is -(4ln(1-2x))/(1-2x)
What is the first derivative of ln^2(1-2x) ?
The first derivative of ln^2(1-2x) is -(4ln(1-2x))/(1-2x)