sum from n=1 to infinity of (n-1)/(3n-1)

解答

n = 1 \sum \infty \frac{n - 1}{3 n - 1}

发散

求解步骤

n = 1 \sum \infty \frac{n - 1}{3 n - 1}

使用级数发散判别法:

发散

= 发散

y^{^{''}} + 1500 y = 320

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\int cos (x) sin (sin (x)) d x

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\int \frac{1}{2 + 2 x} d x