What is the solution for cos(x)dy+(ysin(x)-cos^4(x))dx=0 ?

The solution for cos(x)dy+(ysin(x)-cos^4(x))dx=0 is y=(2x+sin(2x))/(4sec(x))+(c_{1})/(sec(x))

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cos(x)dy+(ysin(x)-cos^4(x))dx=0

cos (x) d y + (y sin (x) - cos^{4} (x)) d x = 0

y = \frac{2 x + sin ( 2 x )}{4 sec ( x )} + \frac{c _{1}}{sec ( x )}

Solution steps

cos (x) d y + (y sin (x) - cos^{4} (x)) d x = 0

Solve linear ODE:

y = \frac{2 x + sin ( 2 x )}{4 sec ( x )} + \frac{c _{1}}{sec ( x )}

y = \frac{2 x + sin ( 2 x )}{4 sec ( x )} + \frac{c _{1}}{sec ( x )}

f (x) = x + 2 sin (x)

\frac{\partial}{\partial x} ((x^{2} + x y)^{3})

2 x y d x + x^{2} d y = 0

x \to 3 + lim (x^{2} + 2 x)

\frac{d y}{d x} = \frac{( 5 y )}{( 2 x + 3 ) ( 3 x + 2 )}

What is the solution for cos(x)dy+(ysin(x)-cos^4(x))dx=0 ?
The solution for cos(x)dy+(ysin(x)-cos^4(x))dx=0 is y=(2x+sin(2x))/(4sec(x))+(c_{1})/(sec(x))