What is the integral of (ln(sqrt(4x)))/x ?

The integral of (ln(sqrt(4x)))/x is 1/4 ln^2(4x)+C

integral of (ln(sqrt(4x)))/x

\int \frac{ln ( 4 x )}{x} d x

\frac{1}{4} ln^{2} (4 x) + C

Solution steps

\int \frac{ln ( 4 x )}{x} d x

Apply u-substitution

= \int \frac{ln ( u )}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{ln ( u )}{u} d u

Apply u-substitution

= \frac{1}{2} \cdot \int v d v

Apply the Power Rule

= \frac{1}{2} \cdot \frac{v ^{2}}{2}

Substitute back

= \frac{1}{2} \cdot \frac{ln ^{2} ( 4 x )}{2}

Simplify

\frac{1}{2} \cdot \frac{ln ^{2} ( 4 x )}{2} : \frac{1}{4} ln^{2} (4 x)

= \frac{1}{4} ln^{2} (4 x)

Add a constant to the solution

= \frac{1}{4} ln^{2} (4 x) + C

\frac{d}{d x} (ln (cosh (4 x)))

\int tan^{2} (2 y) d y

\frac{d}{d x} ((x + 5)^{2})

x \to \infty lim (3 x - 1)

t \to 0 lim (\frac{sin ( 3 t )}{t} + 2)

What is the integral of (ln(sqrt(4x)))/x ?
The integral of (ln(sqrt(4x)))/x is 1/4 ln^2(4x)+C