What is the derivative of y=(x+1)^2 ?

The derivative of y=(x+1)^2 is 2(x+1)

What is the first derivative of y=(x+1)^2 ?

The first derivative of y=(x+1)^2 is 2(x+1)

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derivative of

y = (x + 1)^{2}

2 (x + 1)

Solution steps

\frac{d}{d x} ((x + 1)^{2})

Apply the chain rule:

2 (x + 1) \frac{d}{d x} (x + 1)

= 2 (x + 1) \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 2 (x + 1) \cdot 1

Simplify

= 2 (x + 1)

\frac{d y}{d x} = - x e^{y}

\frac{\partial}{\partial x} (8 sin (x y))

\frac{d}{d y} (\frac{1}{4 y ^{2}})

\frac{\partial}{\partial y} (\frac{3 x y}{x ^{2} + y ^{2}})

2 y \frac{d y}{d x} = x (y^{2} + 1)

What is the derivative of y=(x+1)^2 ?
The derivative of y=(x+1)^2 is 2(x+1)
What is the first derivative of y=(x+1)^2 ?
The first derivative of y=(x+1)^2 is 2(x+1)