What is the solution for 1/(x^4)(dy)/(dx)=19+15y ?

The solution for 1/(x^4)(dy)/(dx)=19+15y is y=(e^{3x^5+c_{1}})/(15)-19/15

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1/(x^4)(dy)/(dx)=19+15y

\frac{1}{x ^{4}} \frac{d y}{d x} = 19 + 15 y

y = \frac{e ^{3 x^{5} + c_{1}}}{15} - \frac{19}{15}

Solution steps

\frac{1}{x ^{4}} \frac{d y}{d x} = 19 + 15 y

Solve separable ODE:

y = \frac{e ^{3 x^{5} + c_{1}}}{15} - \frac{19}{15}

y = \frac{e ^{3 x^{5} + c_{1}}}{15} - \frac{19}{15}

\frac{d ^{2}}{d x ^{2}} (t^{3} (e)^{3 t})

\int (t^{2} + 1) e^{- 2 t} d t

t an g e n t y = 4 sin (x) cos (x), at x = \frac{π}{4}

im pl i c i t 4 x^{2} + 4 x + x y = 4

n \to \infty lim (1000 (1.06)^{n})

What is the solution for 1/(x^4)(dy)/(dx)=19+15y ?
The solution for 1/(x^4)(dy)/(dx)=19+15y is y=(e^{3x^5+c_{1}})/(15)-19/15