What is the derivative of 6e^xt+xt ?

The derivative of 6e^xt+xt is 6te^x+t

What is the first derivative of 6e^xt+xt ?

The first derivative of 6e^xt+xt is 6te^x+t

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\frac{d}{d x} (6 e^{x} t + x t)

6 t e^{x} + t

Solution steps

\frac{d}{d x} (6 e^{x} t + x t)

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 e^{x} t) + \frac{d}{d x} (x t)

\frac{d}{d x} (6 e^{x} t) = 6 t e^{x}

\frac{d}{d x} (x t) = t

= 6 t e^{x} + t

a re a 7 x, 2 x^{2}

\frac{d}{d x} (ln (f (x)) (x))

y^{^{'}} = \frac{sec ( y )}{( x - 1 ) ^{2}}

\frac{d y}{d x} - \frac{2 y}{x} + x^{2} y^{2} = 0

t an g e n t f (x) = 19 x - x^{2}, at x = 9

What is the derivative of 6e^xt+xt ?
The derivative of 6e^xt+xt is 6te^x+t
What is the first derivative of 6e^xt+xt ?
The first derivative of 6e^xt+xt is 6te^x+t