en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area f(x)=ax+b,(0,4)

Solution

area

f (x) = a x + b, (0, 4)

Solution

- a \cdot 8 - 4 b

Solution steps

Apply the area formula:

\int_{0}^{4} ∣ a x + b ∣ d x

Solve

\int_{0}^{4} ∣ a x + b ∣ d x : - a \cdot 8 - 4 b

The area is:

= - a \cdot 8 - 4 b

Popular Examples

tangent of f(x)=(2+4x)(6-5x),\at x=1 tangent of

f (x) = (2 + 4 x) (6 - 5 x), at x = 1

integral from-2 to-4 of (-4)^{-3}

\int_{- 2}^{- 4} (- 4)^{- 3} d x

integral from-1 to 1 of x

\int_{- 1}^{1} x d x

laplacetransform f(t)=t^3e^{2t}laplace transform

f (t) = t^{3} e^{2 t}

derivative of-2+6sin(6x)

\frac{d}{d x} (- 2 + 6 sin (6 x))

Frequently Asked Questions (FAQ)

What is area f(x)=ax+b,(0,4) ?
The answer to area f(x)=ax+b,(0,4) is -a*8-4b