What is the integral of e^{7x}sin(7x) ?

The integral of e^{7x}sin(7x) is -(e^{7x}cos(7x))/(14)+(e^{7x}sin(7x))/(14)+C

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integral of e^{7x}sin(7x)

\int e^{7 x} sin (7 x) d x

- \frac{e ^{7 x} cos ( 7 x )}{14} + \frac{e ^{7 x} sin ( 7 x )}{14} + C

Solution steps

\int e^{7 x} sin (7 x) d x

Apply Integration By Parts

: - \frac{1}{7} e^{7 x} cos (7 x) - \int - e^{7 x} cos (7 x) d x

= - \frac{1}{7} e^{7 x} cos (7 x) - \int - e^{7 x} cos (7 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{7} e^{7 x} cos (7 x) - (- \int e^{7 x} cos (7 x) d x)

Apply Integration By Parts

: \frac{1}{7} e^{7 x} sin (7 x) - \int e^{7 x} sin (7 x) d x

= - \frac{1}{7} e^{7 x} cos (7 x) - (- (\frac{1}{7} e^{7 x} sin (7 x) - \int e^{7 x} sin (7 x) d x))

Therefore

\int e^{7 x} sin (7 x) d x = - \frac{1}{7} e^{7 x} cos (7 x) - (- (\frac{1}{7} e^{7 x} sin (7 x) - \int e^{7 x} sin (7 x) d x))

Isolate

\int e^{7 x} sin (7 x) d x

= - \frac{e ^{7 x} cos ( 7 x )}{14} + \frac{e ^{7 x} sin ( 7 x )}{14}

Add a constant to the solution

= - \frac{e ^{7 x} cos ( 7 x )}{14} + \frac{e ^{7 x} sin ( 7 x )}{14} + C

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What is the integral of e^{7x}sin(7x) ?
The integral of e^{7x}sin(7x) is -(e^{7x}cos(7x))/(14)+(e^{7x}sin(7x))/(14)+C