derivative of \sqrt[3]{2x}

Lösung

\frac{d}{d x} (3 2 x)

\frac{2 ^{\frac{1}{3}}}{3 x ^{\frac{2}{3}}}

Schritte zur Lösung

\frac{d}{d x} (3 2 x)

Wende die Kettenregel an:

\frac{1}{3 ( 2 x ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x)

= \frac{1}{3 ( 2 x ) ^{\frac{2}{3}}} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= \frac{1}{3 ( 2 x ) ^{\frac{2}{3}}} \cdot 2

Vereinfache

\frac{1}{3 ( 2 x ) ^{\frac{2}{3}}} \cdot 2 : \frac{2 ^{\frac{1}{3}}}{3 x ^{\frac{2}{3}}}

= \frac{2 ^{\frac{1}{3}}}{3 x ^{\frac{2}{3}}}

\int \frac{sec ^{3} ( x )}{tan ^{2} ( x )} d x

\frac{\partial}{\partial x} (16 x + 32 y - 1600)

d er i v a t i v e \frac{x}{x + 1}

n = 0 \sum \infty \frac{1}{n ^{3} - n}

\int \frac{1}{x ^{3} - 4 x ^{2} + 3 x} d x