What is the derivative of (-7)/(\sqrt[3]{x)} ?

The derivative of (-7)/(\sqrt[3]{x)} is 7/(3x^{4/3)}

What is the first derivative of (-7)/(\sqrt[3]{x)} ?

The first derivative of (-7)/(\sqrt[3]{x)} is 7/(3x^{4/3)}

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derivative of

\frac{7}{3 x ^{\frac{4}{3}}}

Solution steps

Simplify

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 7 \frac{d}{d x} (x^{- \frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 7 (- \frac{1}{3} x^{- \frac{1}{3} - 1})

Simplify

- 7 (- \frac{1}{3} x^{- \frac{1}{3} - 1}) : \frac{7}{3 x ^{\frac{4}{3}}}

= \frac{7}{3 x ^{\frac{4}{3}}}

\int 2 x \frac{1}{x} d x

\frac{\partial}{\partial x} (e^{x} ln (y))

y = x^{- \frac{2}{5}}

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\int \frac{x ^{2}}{1 - x ^{6}} d x

What is the derivative of (-7)/(\sqrt[3]{x)} ?
The derivative of (-7)/(\sqrt[3]{x)} is 7/(3x^{4/3)}
What is the first derivative of (-7)/(\sqrt[3]{x)} ?
The first derivative of (-7)/(\sqrt[3]{x)} is 7/(3x^{4/3)}