What is the derivative of-5xe^x ?

The derivative of-5xe^x is -5(e^x+e^xx)

What is the first derivative of-5xe^x ?

The first derivative of-5xe^x is -5(e^x+e^xx)

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\frac{d}{d x} (- 5 x e^{x})

- 5 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (- 5 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= - 5 (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= - 5 (1 \cdot e^{x} + e^{x} x)

Simplify

= - 5 (e^{x} + e^{x} x)

e^{5 t s i n (2 t)}

e^{x}, x e^{x}, 0

\frac{\partial}{\partial x} (x^{2} + y^{2} + z^{2} - 25)

y^{^{'}} + 2 y = 2 x + e^{4 x}

\int 2 x cos (9 x) d x

What is the derivative of-5xe^x ?
The derivative of-5xe^x is -5(e^x+e^xx)
What is the first derivative of-5xe^x ?
The first derivative of-5xe^x is -5(e^x+e^xx)