What is the derivative of f(x)=1-3x^2 ?

The derivative of f(x)=1-3x^2 is -6x

What is the first derivative of f(x)=1-3x^2 ?

The first derivative of f(x)=1-3x^2 is -6x

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derivative of

f (x) = 1 - 3 x^{2}

- 6 x

Solution steps

\frac{d}{d x} (1 - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3 x^{2}) = 6 x

= 0 - 6 x

Simplify

= - 6 x

\frac{d}{d x} (\frac{2 x + 3}{3 x + 2})

cos^{2} (x) sin (x) \frac{d y}{d x} + cos^{3} (x) y = 1

x^{3} - 2 x^{2} - 3 x

\frac{\partial}{\partial x} (e^{c o s (x - 2 y)})

\frac{( 7 s + 2 )}{s ^{2} + 6 s + 34}

What is the derivative of f(x)=1-3x^2 ?
The derivative of f(x)=1-3x^2 is -6x
What is the first derivative of f(x)=1-3x^2 ?
The first derivative of f(x)=1-3x^2 is -6x