What is the solution for ((y-2)dy)/(y+3)=((x-1)dx)/(x+4) ?

The solution for ((y-2)dy)/(y+3)=((x-1)dx)/(x+4) is y=-5\W(-(x+4}{5e^{\frac{x+c_{1}+3)/5}})-3

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((y-2)dy)/(y+3)=((x-1)dx)/(x+4)

\frac{( y - 2 ) d y}{y + 3} = \frac{( x - 1 ) d x}{x + 4}

y = - 5 W (- \frac{x + 4}{5 e ^{\frac{x + c _{1} + 3}{5}}}) - 3

Solution steps

\frac{( y - 2 ) d y}{y + 3} = \frac{( x - 1 ) d x}{x + 4}

Solve separable ODE:

y = - 5 W (- \frac{x + 4}{5 e ^{\frac{x + c _{1} + 3}{5}}}) - 3

y = - 5 W (- \frac{x + 4}{5 e ^{\frac{x + c _{1} + 3}{5}}}) - 3

ln (6 x^{3} + 3 x^{2} + 3 x + 3)

\int sin^{4} (3 x) cos^{4} (3 x) d x

f (x) = 9 + 5 x + 2 x e^{x}, at x = 0

\frac{\partial}{\partial y} (2 x y^{4} e^{y} + 2 x y^{3} + y)

f (x) = 19 - x^{2}, at x = 3

What is the solution for ((y-2)dy)/(y+3)=((x-1)dx)/(x+4) ?
The solution for ((y-2)dy)/(y+3)=((x-1)dx)/(x+4) is y=-5\W(-(x+4}{5e^{\frac{x+c_{1}+3)/5}})-3