y^'=2y(5-y)

Lösung

y^{^{'}} = 2 y (5 - y)

y = \frac{5}{e ^{- 10 t + c_{1}} + 1}

Schritte zur Lösung

y^{'} (t) = 2 y (5 - y)

Solve Bernoulli ODE:

y = \frac{5}{e ^{- 10 t + c_{1}} + 1}

y = \frac{5}{e ^{- 10 t + c_{1}} + 1}

t an g e n t f (x) = (x^{2} - 2) (x^{3} - 3 x), at x = - 2

x \to 0 lim (\frac{x ^{2} - 5}{x - 2})

\frac{d ^{2}}{d x ^{2}} x y + 2 x^{2} = 5

\int sin^{3} (x) \cdot cos (x) d x

\frac{\partial}{\partial x} (4 6 x^{2} + 4)