What is the solution for (dy}{dx}=\frac{8y^2)/x ?

The solution for (dy}{dx}=\frac{8y^2)/x is y=-1/(8ln(x)+c_{1)}

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(dy}{dx}=\frac{8y^2)/x

\frac{d y}{d x} = \frac{8 y ^{2}}{x}

y = - \frac{1}{8 ln ( x ) + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{8 y ^{2}}{x}

Solve separable ODE:

y = - \frac{1}{8 ln ( x ) + c _{1}}

y = - \frac{1}{8 ln ( x ) + c _{1}}

\int 5 e^{- 0.2 x} d x

\frac{\partial}{\partial x} (ln (x - e^{x} y))

y^{^{''}} + 16 y = 8 sin (4 t)

\int \frac{1}{x ^{2} + 4 x + 9} d x

y (t + 5) (t + 2) y^{^{'}} + t + 3 = 0

What is the solution for (dy}{dx}=\frac{8y^2)/x ?
The solution for (dy}{dx}=\frac{8y^2)/x is y=-1/(8ln(x)+c_{1)}