What is the d/(dy)(sqrt(y^2-1)) ?

The d/(dy)(sqrt(y^2-1)) is y/(sqrt(y^2-1))

What is the first d/(dy)(sqrt(y^2-1)) ?

The first d/(dy)(sqrt(y^2-1)) is y/(sqrt(y^2-1))

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\frac{d}{d y} (y^{2} - 1)

\frac{y}{y ^{2} - 1}

Solution steps

\frac{d}{d y} (y^{2} - 1)

Apply the chain rule:

\frac{1}{2 y ^{2} - 1} \frac{d}{d y} (y^{2} - 1)

= \frac{1}{2 y ^{2} - 1} \frac{d}{d y} (y^{2} - 1)

\frac{d}{d y} (y^{2} - 1) = 2 y

= \frac{1}{2 y ^{2} - 1} \cdot 2 y

Simplify

\frac{1}{2 y ^{2} - 1} \cdot 2 y : \frac{y}{y ^{2} - 1}

= \frac{y}{y ^{2} - 1}

\int \frac{1}{x ^{2} x ^{2} - 13} d x

\frac{d y}{d x} = 14 x e^{6} x (36 + y^{2})

\int 9 sin^{6} (x) d x

y^{^{'}} + y^{3} x + 9 y = 0

\int x^{5} + 8 x^{- 3} + 2 d x

What is the d/(dy)(sqrt(y^2-1)) ?
The d/(dy)(sqrt(y^2-1)) is y/(sqrt(y^2-1))
What is the first d/(dy)(sqrt(y^2-1)) ?
The first d/(dy)(sqrt(y^2-1)) is y/(sqrt(y^2-1))