What is the limit as h approaches infinity of 2/h+3 ?

The limit as h approaches infinity of 2/h+3 is 3

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limit as h approaches infinity of 2/h+3

h \to \infty lim (\frac{2}{h} + 3)

3

Solution steps

h \to \infty lim (\frac{2}{h} + 3)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= h \to \infty lim (\frac{2}{h}) + h \to \infty lim (3)

h \to \infty lim (\frac{2}{h}) = 0

h \to \infty lim (3) = 3

= 0 + 3

Simplify

= 3

4 x^{4} - 4 x^{2}, 5 x^{2}, 0, 1.5

\frac{d}{d x} (sec (x) - \frac{1}{x ^{3}} + 5)

x \to 0 lim (x ln (tan (2 x)))

8 y^{^{''}} - 8 y^{^{'}} + 4 y = 0

What is the limit as h approaches infinity of 2/h+3 ?
The limit as h approaches infinity of 2/h+3 is 3