What is the integral of (\sqrt[4]{x}+\sqrt[5]{x}) ?

The integral of (\sqrt[4]{x}+\sqrt[5]{x}) is 4/5 x^{5/4}+5/6 x^{6/5}+C

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integral of (\sqrt[4]{x}+\sqrt[5]{x})

\frac{4}{5} x^{\frac{5}{4}} + \frac{5}{6} x^{\frac{6}{5}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{4}{5} x^{\frac{5}{4}} + \frac{5}{6} x^{\frac{6}{5}}

Add a constant to the solution

= \frac{4}{5} x^{\frac{5}{4}} + \frac{5}{6} x^{\frac{6}{5}} + C

(9 x + 0.8 x^{2} + 0.07 x^{3})^{^{'}}

y = cos (x)

ln (\frac{1 + x}{1 - x})

\frac{d}{d x} (lo g_{5} (4 x^{2} + 5 x - 8))

\frac{\partial}{\partial x} (x y + \frac{y}{x})

What is the integral of (\sqrt[4]{x}+\sqrt[5]{x}) ?
The integral of (\sqrt[4]{x}+\sqrt[5]{x}) is 4/5 x^{5/4}+5/6 x^{6/5}+C