What is the tangent of y=4x^3-4x,(1,0) ?

The tangent of y=4x^3-4x,(1,0) is y=8x-8

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tangent of y=4x^3-4x,(1,0)

tangent of

y = 4 x^{3} - 4 x, (1, 0)

y = 8 x - 8

Solution steps

Find the slope of

y = 4 x^{3} - 4 x : \frac{d y}{d x} = 12 x^{2} - 4

Compute the slope of

y = 4 x^{3} - 4 x

(1, 0) : m = 8

Find the line with slope m=

8

and passing through

(1, 0) : y = 8 x - 8

y = 8 x - 8

\int (x + 5) (x^{3} + 5 x - 10) d x

\int - x^{2} ln (x) d x

\int 24 x^{- 3} d x

\int_{0}^{\frac{π}{2}} 8 cos^{5} (x) d x

\frac{d y}{d x} = 3 x - y

What is the tangent of y=4x^3-4x,(1,0) ?
The tangent of y=4x^3-4x,(1,0) is y=8x-8