What is the limit as x approaches 0 of ln(1/(x^2)) ?

The limit as x approaches 0 of ln(1/(x^2)) is diverges

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limit as x approaches 0 of ln(1/(x^2))

x \to 0 lim (ln (\frac{1}{x ^{2}}))

diverges

Solution steps

x \to 0 lim (ln (\frac{1}{x ^{2}}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (ln (\frac{1}{x ^{2}})) = \infty

x \to 0 - lim (ln (\frac{1}{x ^{2}})) = -

Does not exist

= diverges

\frac{\partial}{\partial z} (y^{2} z)

\int_{0}^{N} e^{- s t} cos (3 t) d t

y = 4 x - 3 x^{2}, (2, - 4)

(x + 2)^{2}

\frac{d y}{d x} - \frac{1}{x} y = - 9

What is the limit as x approaches 0 of ln(1/(x^2)) ?
The limit as x approaches 0 of ln(1/(x^2)) is diverges