What is the tangent of y=(x^2-1)/(x^2+x+1),(1,0) ?

The tangent of y=(x^2-1)/(x^2+x+1),(1,0) is y= 2/3 x-2/3

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tangent of y=(x^2-1)/(x^2+x+1),(1,0)

tangent of

y = \frac{x ^{2} - 1}{x ^{2} + x + 1}, (1, 0)

y = \frac{2}{3} x - \frac{2}{3}

Solution steps

Find the slope of

y = \frac{x ^{2} - 1}{x ^{2} + x + 1} : \frac{d y}{d x} = \frac{x ^{2} + 4 x + 1}{( x ^{2} + x + 1 ) ^{2}}

Compute the slope of

y = \frac{x ^{2} - 1}{x ^{2} + x + 1}

(1, 0) : m = \frac{2}{3}

Find the line with slope m=

\frac{2}{3}

and passing through

(1, 0) : y = \frac{2}{3} x - \frac{2}{3}

y = \frac{2}{3} x - \frac{2}{3}

y^{^{''}} + 4 y^{^{'}} + 5 y = cos (2 x)

\frac{1}{( x ^{2} + 1 ) \cdot x}

\int x sin (\frac{1}{4} x) d x

\frac{\partial}{\partial s} (3 s^{2} + t^{2})

What is the tangent of y=(x^2-1)/(x^2+x+1),(1,0) ?
The tangent of y=(x^2-1)/(x^2+x+1),(1,0) is y= 2/3 x-2/3