What is the derivative of 1/2 (x^4+7) ?

The derivative of 1/2 (x^4+7) is 2x^3

What is the first derivative of 1/2 (x^4+7) ?

The first derivative of 1/2 (x^4+7) is 2x^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{1}{2} (x^{4} + 7)

2 x^{3}

Solution steps

\frac{d}{d x} (\frac{1}{2} (x^{4} + 7))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x^{4} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d}{d x} (x^{4}) + \frac{d}{d x} (7))

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (7) = 0

= \frac{1}{2} (4 x^{3} + 0)

Simplify

\frac{1}{2} (4 x^{3} + 0) : 2 x^{3}

= 2 x^{3}

\int e^{x} 0.2 d x

f (x) = x^{3} - 2 x^{2} - 6 x + 6, at x = 0

\int (3 x)^{2} d x

\frac{d}{d x} (- x y^{3})

(- 2, 4), (- 1, - 1)

What is the derivative of 1/2 (x^4+7) ?
The derivative of 1/2 (x^4+7) is 2x^3
What is the first derivative of 1/2 (x^4+7) ?
The first derivative of 1/2 (x^4+7) is 2x^3