What is the solution for 81y^{''}-16y=0 ?

The solution for 81y^{''}-16y=0 is y=c_{1}e^{(4t)/9}+c_{2}e^{-(4t)/9}

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81y^{''}-16y=0

81 y^{^{''}} - 16 y = 0

y = c_{1} e^{\frac{4 t}{9}} + c_{2} e^{- \frac{4 t}{9}}

Solution steps

81 y^{''} (t) - 16 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{4 t}{9}} + c_{2} e^{- \frac{4 t}{9}}

y = c_{1} e^{\frac{4 t}{9}} + c_{2} e^{- \frac{4 t}{9}}

x \to 7 lim (0)

\int_{0}^{5} x^{2} - 5 x d x

(1 + x) y^{^{'}} + 2 y = \frac{sin ( x )}{1 + x}

\int sin (5 θ) sin (θ) d θ

\frac{\partial}{\partial x} (9 x e^{4 x y})

What is the solution for 81y^{''}-16y=0 ?
The solution for 81y^{''}-16y=0 is y=c_{1}e^{(4t)/9}+c_{2}e^{-(4t)/9}