integral from-1 to 0 of 1/(1+x^2)

Lösung

\int_{- 1}^{0} \frac{1}{1 + x ^{2}} d x

\frac{π}{4}

Dezimale

0.78539 \dots

Schritte zur Lösung

\int_{- 1}^{0} \frac{1}{1 + x ^{2}} d x

Nutze das gemeinsame Integral :

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{- 1}^{0}

Berechne die Grenzen:

\frac{π}{4}

= \frac{π}{4}

\int_{0}^{1} - 1 (x^{2} + 1) e^{- x} d x

\frac{\partial}{\partial x} (7 - 3 x^{2} - 3 y^{2})

s l o p e (2.4) (6.12)

x \to 0 + lim ((x + 1)^{in x})

n = 0 \sum \infty \frac{5 ^{2 n}}{n !}