5t*(dy)/(dt)+4y=sqrt(t)

Lösung

5 t \cdot \frac{d y}{d t} + 4 y = t

y = \frac{2 t ^{\frac{1}{2}}}{13} + \frac{c _{1}}{t ^{\frac{4}{5}}}

Schritte zur Lösung

5 t \cdot \frac{d y}{d t} + 4 y = t

Solve linear ODE:

y = \frac{2 t ^{\frac{1}{2}}}{13} + \frac{c _{1}}{t ^{\frac{4}{5}}}

y = \frac{2 t ^{\frac{1}{2}}}{13} + \frac{c _{1}}{t ^{\frac{4}{5}}}

\int_{2}^{\infty} \frac{2}{t ^{2} - 1} d t

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