integral from 2 to 4 of (2-x^2)-(10-6x)

Lösung

\int_{2}^{4} (2 - x^{2}) - (10 - 6 x) d x

\frac{4}{3}

Dezimale

1.33333 \dots

Schritte zur Lösung

\int_{2}^{4} 2 - x^{2} - (10 - 6 x) d x

Vereinfache

= \int_{2}^{4} - x^{2} + 6 x - 8 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{2}^{4} x^{2} d x + \int_{2}^{4} 6 x d x - \int_{2}^{4} 8 d x

\int_{2}^{4} x^{2} d x = \frac{56}{3}

\int_{2}^{4} 6 x d x = 36

\int_{2}^{4} 8 d x = 16

= - \frac{56}{3} + 36 - 16

Vereinfache

- \frac{56}{3} + 36 - 16 : \frac{4}{3}

= \frac{4}{3}

\frac{\partial}{\partial h} (\frac{A}{h + 5 h})

\int x ln (\frac{x}{2}) d x

\frac{d}{d x} (x + 5 - 3)

\int e^{x} \cdot cos (4 x) d x

x \to \infty lim (2 x - 4)