What is the integral from 1 to infinity of x/(x^2+4) ?

The integral from 1 to infinity of x/(x^2+4) is diverges

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integral from 1 to infinity of x/(x^2+4)

\int_{1}^{\infty} \frac{x}{x ^{2} + 4} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{x}{x ^{2} + 4} d x

Compute the indefinite integral:

\int \frac{x}{x ^{2} + 4} d x = \frac{1}{2} ln x^{2} + 4 + C

Compute the boundaries:

\int_{1}^{\infty} \frac{x}{x ^{2} + 4} d x =

diverges

= diverges

\frac{d}{d x} (\frac{3 π}{2})

x \to 0 lim (tan^{x} (9 x))

\frac{\partial}{\partial x} (x^{3} - 3 x y + y^{3} - 2)

\frac{4 s + 1}{2 s ^{2} - 5 s + 6}

f (x) = π^{x^{2}}

What is the integral from 1 to infinity of x/(x^2+4) ?
The integral from 1 to infinity of x/(x^2+4) is diverges