What is the limit as x approaches 1 of (8x+1)/(x+3) ?

The limit as x approaches 1 of (8x+1)/(x+3) is 9/4

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limit as x approaches 1 of (8x+1)/(x+3)

x \to 1 lim (\frac{8 x + 1}{x + 3})

\frac{9}{4}

Decimal

2.25

Solution steps

x \to 1 lim (\frac{8 x + 1}{x + 3})

Plug in the value

x = 1

= \frac{8 \cdot 1 + 1}{1 + 3}

Simplify

= \frac{9}{4}

s l o p e in t erce pt (- 3, 2), (- 1, - 1)

d er i v a t i v e x x^{2} + 9

y^{^{''}} + 2 y^{^{'}} + 10 y = 0, y (0) = 3, y^{^{'}} (0) = - 1

\frac{d}{d x} (\frac{e ^{6 x}}{x})

x \to 3 lim (x + 3)

What is the limit as x approaches 1 of (8x+1)/(x+3) ?
The limit as x approaches 1 of (8x+1)/(x+3) is 9/4