{
"query": {
"display": "$$\\sum_{n=1}^{\\infty\\:}\\frac{5}{n^{2}+16}$$",
"symbolab_question": "BIG_OPERATOR#\\sum _{n=1}^{\\infty }\\frac{5}{n^{2}+16}"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Series",
"subTopic": "Convergence",
"default": "\\mathrm{converges}"
},
"steps": {
"type": "interim",
"title": "Check convergence of $$\\sum_{n=1}^{\\infty\\:}\\frac{5}{n^{2}+16}:{\\quad}$$converges",
"input": "\\sum_{n=1}^{\\infty\\:}\\frac{5}{n^{2}+16}",
"steps": [
{
"type": "step",
"primary": "Apply the constant multiplication rule: $$\\sum{c\\cdot{a_{n}}}=c\\cdot\\sum{a_{n}}$$",
"result": "=5\\cdot\\:\\sum_{n=1}^{\\infty\\:}\\frac{1}{n^{2}+16}"
},
{
"type": "interim",
"title": "Apply Series Comparison Test:$${\\quad}$$converges",
"input": "\\sum_{n=1}^{\\infty\\:}\\frac{1}{n^{2}+16}",
"steps": [
{
"type": "definition",
"title": "Comparison Test:",
"text": "Let $$\\sum\\:a_n,\\:\\sum\\:b_n\\:$$be two positive sequences such that for all $$n,\\:\\quad\\:a_n\\le\\:b_n$$<br/>If $$\\sum\\:b_n\\:$$converges, so does $$\\sum\\:a_n$$<br/>If $$\\sum\\:a_n\\:$$diverges, so does $$\\sum\\:b_n$$",
"secondary": [
"$$\\sum_{n=1}^{\\infty\\:}\\frac{1}{n^{2}+16}\\le\\:\\sum_{n=1}^{\\infty\\:}\\frac{1}{n^{2}}$$"
]
},
{
"type": "interim",
"title": "Check convergence of $$\\sum_{n=1}^{\\infty\\:}\\frac{1}{n^{2}}:{\\quad}$$converges",
"input": "\\sum_{n=1}^{\\infty\\:}\\frac{1}{n^{2}}",
"steps": [
{
"type": "interim",
"title": "Apply p-Series Test:$${\\quad}$$converges",
"input": "\\sum_{n=1}^{\\infty\\:}\\frac{1}{n^{2}}",
"steps": [
{
"type": "definition",
"title": "p-Series Test:",
"text": "If the series is of the form $$\\sum_{n=1}^{\\infty}\\frac{1}{n^p},\\:$$where $$p\\gt0$$<br/>$${\\quad}$$If $$p>1,\\:$$then the p-series converges<br/>$${\\quad}$$If $$0<p\\le1,\\:$$then the p-series diverges"
},
{
"type": "step",
"primary": "$$p=2,\\:\\:p>1,\\:$$by the p-Series test criteria",
"result": "=\\mathrm{converges}"
}
],
"meta": {
"interimType": "Series Apply P Series Test 0Eq"
}
},
{
"type": "step",
"result": "=\\mathrm{converges}"
}
],
"meta": {
"solvingClass": "Series",
"interimType": "Sum Convergence Check 1Eq"
}
},
{
"type": "step",
"primary": "By the comparison test",
"result": "=\\mathrm{converges}"
}
],
"meta": {
"interimType": "Series Apply Comparison Test 0Eq"
}
},
{
"type": "step",
"result": "=5\\mathrm{converges}"
},
{
"type": "step",
"result": "=\\mathrm{converges}"
}
],
"meta": {
"solvingClass": "Series",
"practiceLink": "/practice/series-practice#area=main&subtopic=Comparison%20Test",
"practiceTopic": "Series Comparison Test"
}
}
}
Solution
Solution
Solution steps
Apply the constant multiplication rule:
Apply Series Comparison Test:converges
Popular Examples
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Frequently Asked Questions (FAQ)
What is the sum from n=1 to infinity of 5/(n^2+16) ?
The sum from n=1 to infinity of 5/(n^2+16) is converges