(\partial)/(\partial t)(zy^2(t+1))

解答

\frac{\partial}{\partial t} (z y^{2} (t + 1))

z y^{2}

求解步骤

\frac{\partial}{\partial t} (z y^{2} (t + 1))

将

z, y

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= z y^{2} \frac{\partial}{\partial t} (t + 1)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z y^{2} (\frac{\partial}{\partial t} (t) + \frac{\partial}{\partial t} (1))

\frac{\partial}{\partial t} (t) = 1

\frac{\partial}{\partial t} (1) = 0

= z y^{2} (1 + 0)

化简

= z y^{2}

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