What is the integral of e^{ax}sin(bx) ?

The integral of e^{ax}sin(bx) is -(be^{ax}cos(bx))/(b^2+a^2)+(ae^{ax}sin(bx))/(b^2+a^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{ax}sin(bx)

\int e^{a x} sin (b x) d x

- \frac{b e ^{a x} cos ( b x )}{b ^{2} + a ^{2}} + \frac{a e ^{a x} sin ( b x )}{b ^{2} + a ^{2}} + C

Solution steps

\int e^{a x} sin (b x) d x

Apply Integration By Parts

: - e^{a x} \frac{1}{b} cos (b x) - \int - a e^{a x} \frac{1}{b} cos (b x) d x

= - e^{a x} \frac{1}{b} cos (b x) - \int - a e^{a x} \frac{1}{b} cos (b x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{a x} \frac{1}{b} cos (b x) - (- a \frac{1}{b} \cdot \int e^{a x} cos (b x) d x)

Simplify

- a \frac{1}{b} : - \frac{a}{b}

= - e^{a x} \frac{1}{b} cos (b x) - (- \frac{a}{b} \cdot \int e^{a x} cos (b x) d x)

Apply Integration By Parts

: e^{a x} \frac{1}{b} sin (b x) - \int e^{a x} a \frac{1}{b} sin (b x) d x

= - e^{a x} \frac{1}{b} cos (b x) - (- \frac{a}{b} (e^{a x} \frac{1}{b} sin (b x) - \int e^{a x} a \frac{1}{b} sin (b x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - e^{a x} \frac{1}{b} cos (b x) - (- \frac{a}{b} (e^{a x} \frac{1}{b} sin (b x) - a \frac{1}{b} \cdot \int e^{a x} sin (b x) d x))

Simplify

a \frac{1}{b} : \frac{a}{b}

= - e^{a x} \frac{1}{b} cos (b x) - (- \frac{a}{b} (e^{a x} \frac{1}{b} sin (b x) - \frac{a}{b} \cdot \int e^{a x} sin (b x) d x))

Therefore

\int e^{a x} sin (b x) d x = - e^{a x} \frac{1}{b} cos (b x) - (- \frac{a}{b} (e^{a x} \frac{1}{b} sin (b x) - \frac{a}{b} \cdot \int e^{a x} sin (b x) d x))

Isolate

\int e^{a x} sin (b x) d x

= - \frac{b e ^{a x} cos ( b x )}{b ^{2} + a ^{2}} + \frac{a e ^{a x} sin ( b x )}{b ^{2} + a ^{2}}

Add a constant to the solution

= - \frac{b e ^{a x} cos ( b x )}{b ^{2} + a ^{2}} + \frac{a e ^{a x} sin ( b x )}{b ^{2} + a ^{2}} + C

\frac{\partial}{\partial x} (e^{- x} sin (y) z)

n = 1 \sum \infty \frac{3 n}{6 n + 13}

\int \frac{1}{x ln ^{2} ( x )} d x

f (x) = cos (4 x + 1)

\int_{- 2}^{0} (4 - x) d x

What is the integral of e^{ax}sin(bx) ?
The integral of e^{ax}sin(bx) is -(be^{ax}cos(bx))/(b^2+a^2)+(ae^{ax}sin(bx))/(b^2+a^2)+C