taylor x^2+3x

Lösung

taylor

x^{2} + 3 x

3 x + x^{2}

Schritte zur Lösung

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( x ^{2} + 3 x ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{2} + 3 x ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{2} + 3 x ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{3}{1 !} x + \frac{2}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Fasse zusammen

= 3 x + x^{2}

\frac{d}{d x} (- \frac{2}{( 2 x + 3 ) ^{2}})

\int x^{4} - 2 x^{3} + x^{2} d x

f (x) = 4 e^{2 x}

d er i v a t i v e F (x) = (3 x^{6} + 4 x^{3})^{4}

\frac{d y}{d t} = - 4 y + 9 e^{- t}