What is the derivative of ax+ln(x) ?

The derivative of ax+ln(x) is a+1/x

What is the first derivative of ax+ln(x) ?

The first derivative of ax+ln(x) is a+1/x

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\frac{d}{d x} (a x + ln (x))

a + \frac{1}{x}

Solution steps

\frac{d}{d x} (a x + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (a x) = a

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= a + \frac{1}{x}

\int (x^{2} + y^{2})^{\frac{1}{2}} d x

\int - x e^{- x} d x

\int (4 x + 7) d x

x \to 3 lim (8)

What is the derivative of ax+ln(x) ?
The derivative of ax+ln(x) is a+1/x
What is the first derivative of ax+ln(x) ?
The first derivative of ax+ln(x) is a+1/x