What is the sum from n=0 to infinity of (1+2/n)^{3n} ?

The sum from n=0 to infinity of (1+2/n)^{3n} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (1+2/n)^{3n}

n = 0 \sum \infty (1 + \frac{2}{n})^{3 n}

diverges

Solution steps

n = 1 \sum \infty (1 + \frac{2}{n})^{3 n}

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d x} (x^{a} (1 - x)^{b})

x \to - 8 lim (\frac{- 5 x}{x + 8})

\int \frac{v}{0.122 - 0.0007 v ^{2}} d v

\int \frac{9 x ^{2} - 49}{x ^{3}} d x

7 (t - 7)

What is the sum from n=0 to infinity of (1+2/n)^{3n} ?
The sum from n=0 to infinity of (1+2/n)^{3n} is diverges