What is the solution for (dy)/(dx)+6x^2y=e^{-2x^3} ?

The solution for (dy)/(dx)+6x^2y=e^{-2x^3} is y= x/(e^{2x^3)}+(c_{1})/(e^{2x^3)}

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(dy)/(dx)+6x^2y=e^{-2x^3}

\frac{d y}{d x} + 6 x^{2} y = e^{- 2 x^{3}}

y = \frac{x}{e ^{2 x^{3}}} + \frac{c _{1}}{e ^{2 x^{3}}}

Solution steps

\frac{d y}{d x} + 6 x^{2} y = e^{- 2 x^{3}}

Solve linear ODE:

y = \frac{x}{e ^{2 x^{3}}} + \frac{c _{1}}{e ^{2 x^{3}}}

y = \frac{x}{e ^{2 x^{3}}} + \frac{c _{1}}{e ^{2 x^{3}}}

\frac{d}{d x} (arccsc (2 x))

\frac{d y}{d t} - 3 y = 3 e^{4 t}

d er i v a t i v e y = 2 x^{2} lo g_{e} (x) - x^{2}

\frac{d y}{d x} = \frac{y}{x} + \frac{( y ^{2} )}{x ^{2}}

\frac{d}{d x} (\frac{3}{4 x - 5})

What is the solution for (dy)/(dx)+6x^2y=e^{-2x^3} ?
The solution for (dy)/(dx)+6x^2y=e^{-2x^3} is y= x/(e^{2x^3)}+(c_{1})/(e^{2x^3)}