What is the tangent of-3x^{3/2}-1,\at x=4 ?

The tangent of-3x^{3/2}-1,\at x=4 is y=-9x+11

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tangent of-3x^{3/2}-1,\at x=4

tangent of

- 3 x^{\frac{3}{2}} - 1, at x = 4

y = - 9 x + 11

Solution steps

Find the tangent point:

(4, - 25)

Find the slope of

y = - 3 x^{\frac{3}{2}} - 1 : \frac{d y}{d x} = - \frac{9 x ^{\frac{1}{2}}}{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 9

Find the line with slope m=

- 9

and passing through

(4, - 25) : y = - 9 x + 11

y = - 9 x + 11

\frac{\partial}{\partial x} (\frac{e ^{y}}{x + y ^{2}})

d er i v a t i v e f (x) = 2 x^{2} - 3 x + 4

\int \frac{7}{( x ^{2} + 3 x - 10 )} d x

x \to 0 lim (x^{2} \cdot sin (\frac{1}{x ^{2}}))

\int sin^{5} (d) x d x

What is the tangent of-3x^{3/2}-1,\at x=4 ?
The tangent of-3x^{3/2}-1,\at x=4 is y=-9x+11