{
"query": {
"display": "derivative of $$1-\\cos\\left(2x\\right)$$",
"symbolab_question": "PRE_CALC#derivative 1-\\cos(2x)"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Derivatives",
"default": "2\\sin(2x)",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(1-\\cos\\left(2x\\right)\\right)=2\\sin\\left(2x\\right)$$",
"input": "\\frac{d}{dx}\\left(1-\\cos\\left(2x\\right)\\right)",
"steps": [
{
"type": "interim",
"title": "Simplify $$1-\\cos\\left(2x\\right):{\\quad}2\\sin^{2}\\left(x\\right)$$",
"input": "1-\\cos\\left(2x\\right)",
"steps": [
{
"type": "interim",
"title": "Rewrite using trig identities",
"input": "1-\\cos\\left(2x\\right)",
"result": "=2\\sin^{2}\\left(x\\right)",
"steps": [
{
"type": "step",
"primary": "Use the Double Angle identity: $$\\cos\\left(2x\\right)=1-2\\sin^{2}\\left(x\\right)$$",
"result": "=1-\\left(1-2\\sin^{2}\\left(x\\right)\\right)"
},
{
"type": "interim",
"title": "Simplify $$1-\\left(1-2\\sin^{2}\\left(x\\right)\\right):{\\quad}2\\sin^{2}\\left(x\\right)$$",
"input": "1-\\left(1-2\\sin^{2}\\left(x\\right)\\right)",
"result": "=2\\sin^{2}\\left(x\\right)",
"steps": [
{
"type": "interim",
"title": "$$-\\left(1-2\\sin^{2}\\left(x\\right)\\right):{\\quad}-1+2\\sin^{2}\\left(x\\right)$$",
"input": "-\\left(1-2\\sin^{2}\\left(x\\right)\\right)",
"result": "=1-1+2\\sin^{2}\\left(x\\right)",
"steps": [
{
"type": "step",
"primary": "Distribute parentheses",
"result": "=-\\left(1\\right)-\\left(-2\\sin^{2}\\left(x\\right)\\right)"
},
{
"type": "step",
"primary": "Apply minus-plus rules",
"secondary": [
"$$-\\left(-a\\right)=a,\\:\\:\\:-\\left(a\\right)=-a$$"
],
"result": "=-1+2\\sin^{2}\\left(x\\right)"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "$$1-1=0$$",
"result": "=2\\sin^{2}\\left(x\\right)"
}
],
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"interimType": "Generic Simplify Specific 1Eq",
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],
"meta": {
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"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\frac{d}{dx}\\left(2\\sin^{2}\\left(x\\right)\\right)"
},
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=2\\frac{d}{dx}\\left(\\sin^{2}\\left(x\\right)\\right)"
},
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}2\\sin\\left(x\\right)\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)$$",
"input": "\\frac{d}{dx}\\left(\\sin^{2}\\left(x\\right)\\right)",
"result": "=2\\sin\\left(x\\right)\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=u^{2},\\:\\:u=\\sin\\left(x\\right)$$"
],
"result": "=\\frac{d}{du}\\left(u^{2}\\right)\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{d}{du}\\left(u^{2}\\right)=2u$$",
"input": "\\frac{d}{du}\\left(u^{2}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=2u^{2-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "step",
"primary": "Simplify",
"result": "=2u",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
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}
},
{
"type": "step",
"result": "=2u\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)"
},
{
"type": "step",
"primary": "Substitute back $$u=\\sin\\left(x\\right)$$",
"result": "=2\\sin\\left(x\\right)\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
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}
},
{
"type": "interim",
"title": "$$\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)=\\cos\\left(x\\right)$$",
"input": "\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{dx}\\left(\\sin\\left(x\\right)\\right)=\\cos\\left(x\\right)$$",
"result": "=\\cos\\left(x\\right)"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
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}
},
{
"type": "step",
"result": "=2\\cdot\\:2\\sin\\left(x\\right)\\cos\\left(x\\right)"
},
{
"type": "interim",
"title": "Simplify $$2\\cdot\\:2\\sin\\left(x\\right)\\cos\\left(x\\right):{\\quad}2\\sin\\left(2x\\right)$$",
"input": "2\\cdot\\:2\\sin\\left(x\\right)\\cos\\left(x\\right)",
"result": "=2\\sin\\left(2x\\right)",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:2=4$$",
"result": "=4\\sin\\left(x\\right)\\cos\\left(x\\right)"
},
{
"type": "interim",
"title": "Rewrite using trig identities",
"input": "4\\cos\\left(x\\right)\\sin\\left(x\\right)",
"result": "=2\\sin\\left(2x\\right)",
"steps": [
{
"type": "step",
"primary": "Use the Double Angle identity: $$2\\sin\\left(x\\right)\\cos\\left(x\\right)=\\sin\\left(2x\\right)$$",
"secondary": [
"$$\\sin\\left(x\\right)\\cos\\left(x\\right)=\\frac{\\sin\\left(2x\\right)}{2}$$"
],
"result": "=4\\cdot\\:\\frac{\\sin\\left(2x\\right)}{2}"
},
{
"type": "interim",
"title": "Simplify $$4\\cdot\\:\\frac{\\sin\\left(2x\\right)}{2}:{\\quad}2\\sin\\left(2x\\right)$$",
"input": "4\\cdot\\:\\frac{\\sin\\left(2x\\right)}{2}",
"result": "=2\\sin\\left(2x\\right)",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{\\sin\\left(2x\\right)\\cdot\\:4}{2}"
},
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{4}{2}=2$$",
"result": "=2\\sin\\left(2x\\right)"
}
],
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"solvingClass": "Derivatives",
"practiceLink": "/practice/derivatives-practice",
"practiceTopic": "Derivatives"
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},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "y=2\\sin(2x)"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
derivative of
Solution
Solution steps
Simplify
Take the constant out:
Apply the chain rule:
Simplify
Graph
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Frequently Asked Questions (FAQ)
What is the derivative of 1-cos(2x) ?
The derivative of 1-cos(2x) is 2sin(2x)What is the first derivative of 1-cos(2x) ?
The first derivative of 1-cos(2x) is 2sin(2x)