What is the derivative of 1-cos(2x) ?

The derivative of 1-cos(2x) is 2sin(2x)

What is the first derivative of 1-cos(2x) ?

The first derivative of 1-cos(2x) is 2sin(2x)

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derivative of

1 - cos (2 x)

2 sin (2 x)

Solution steps

\frac{d}{d x} (1 - cos (2 x))

Simplify

1 - cos (2 x) : 2 sin^{2} (x)

= \frac{d}{d x} (2 sin^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin^{2} (x))

Apply the chain rule:

2 sin (x) \frac{d}{d x} (sin (x))

= 2 sin (x) \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= 2 \cdot 2 sin (x) cos (x)

Simplify

2 \cdot 2 sin (x) cos (x) : 2 sin (2 x)

= 2 sin (2 x)

f (x) = (x^{2} - 7) (x^{2} + 6)

\frac{\partial}{\partial y} (e^{x} cos (y))

\frac{5}{( s ^{2} + 5 ^{2} ) ^{2}}

n = 3 \sum \infty \frac{3 ^{n}}{1 1 ^{n}}

\int \frac{y ^{2} - 49}{y} d y

What is the derivative of 1-cos(2x) ?
The derivative of 1-cos(2x) is 2sin(2x)
What is the first derivative of 1-cos(2x) ?
The first derivative of 1-cos(2x) is 2sin(2x)