What is the integral of 1/(x(\sqrt[5]{x))} ?

The integral of 1/(x(\sqrt[5]{x))} is -5/(\sqrt[5]{x)}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/(x(\sqrt[5]{x))}

\int \frac{1}{x ( 5 x )} d x

- \frac{5}{5 x} + C

Solution steps

\int \frac{1}{x 5 x} d x

Simplify

x 5 x : x^{\frac{6}{5}}

= \int \frac{1}{x ^{\frac{6}{5}}} d x

Apply the Power Rule

= - \frac{5}{5 x}

Add a constant to the solution

= - \frac{5}{5 x} + C

\int x e^{- 1} d x

a re a y = 1 + 3 x, x = 0, x = 8, y = 0

\frac{d}{d x} (\frac{2 x ^{2} - 1}{( x - 1 ) ^{2}})

\frac{\partial}{\partial x} (x^{8} + 2^{y} + x^{y})

y^{^{'}} = \frac{x}{y ^{2}}

What is the integral of 1/(x(\sqrt[5]{x))} ?
The integral of 1/(x(\sqrt[5]{x))} is -5/(\sqrt[5]{x)}+C