What is the derivative of 2x^{-3} ?

The derivative of 2x^{-3} is -6/(x^4)

What is the first derivative of 2x^{-3} ?

The first derivative of 2x^{-3} is -6/(x^4)

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\frac{d}{d x} (2 x^{- 3})

- \frac{6}{x ^{4}}

Solution steps

\frac{d}{d x} (2 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 3 x^{- 3 - 1})

Simplify

2 (- 3 x^{- 3 - 1}) : - \frac{6}{x ^{4}}

= - \frac{6}{x ^{4}}

f (x) = \frac{4}{x}

\int \frac{3 x ^{4} - x ^{3} + 6 x ^{2}}{x ^{4}} d x

y = 12 - x^{2}, y = x^{2} - 6

\frac{d}{d x} ((cos (7 x))^{x})

x, \frac{1}{2} x, 0, 25

What is the derivative of 2x^{-3} ?
The derivative of 2x^{-3} is -6/(x^4)
What is the first derivative of 2x^{-3} ?
The first derivative of 2x^{-3} is -6/(x^4)