What is the derivative of (3^x/(ln(3))) ?

The derivative of (3^x/(ln(3))) is 3^x

What is the first derivative of (3^x/(ln(3))) ?

The first derivative of (3^x/(ln(3))) is 3^x

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\frac{d}{d x} (\frac{3 ^{x}}{ln ( 3 )})

3^{x}

Solution steps

\frac{d}{d x} (\frac{3 ^{x}}{ln ( 3 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{ln ( 3 )} \frac{d}{d x} (3^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= \frac{1}{ln ( 3 )} \cdot 3^{x} ln (3)

Simplify

\frac{1}{ln ( 3 )} \cdot 3^{x} ln (3) : 3^{x}

= 3^{x}

x \to 0 lim (\frac{x}{x ^{2} - 7 x + 1})

y^{^{'}} = \frac{x ^{2} y - y}{y + 1}

\int 2 x - 5 d x

x \to 2 lim ((3 - x)^{2})

\int (3 x^{2} - 7 x)^{5} (6 x - 7) d x

What is the derivative of (3^x/(ln(3))) ?
The derivative of (3^x/(ln(3))) is 3^x
What is the first derivative of (3^x/(ln(3))) ?
The first derivative of (3^x/(ln(3))) is 3^x