What is the derivative of sqrt(x+19) ?

The derivative of sqrt(x+19) is 1/(2sqrt(x+19))

What is the first derivative of sqrt(x+19) ?

The first derivative of sqrt(x+19) is 1/(2sqrt(x+19))

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derivative of

x + 19

\frac{1}{2 x + 19}

Solution steps

\frac{d}{d x} (x + 19)

Apply the chain rule:

\frac{1}{2 x + 19} \frac{d}{d x} (x + 19)

= \frac{1}{2 x + 19} \frac{d}{d x} (x + 19)

\frac{d}{d x} (x + 19) = 1

= \frac{1}{2 x + 19} \cdot 1

Simplify

= \frac{1}{2 x + 19}

t^{\frac{1}{3}}

x \to π lim (csc^{2} (x))

\frac{\partial}{\partial x} (\frac{1}{b} \cdot (a - p (b, x)))

\frac{d}{d x} (\frac{3 x}{9 - x ^{2}})

t^{3} - 3 t

What is the derivative of sqrt(x+19) ?
The derivative of sqrt(x+19) is 1/(2sqrt(x+19))
What is the first derivative of sqrt(x+19) ?
The first derivative of sqrt(x+19) is 1/(2sqrt(x+19))