What is area 1/x , 1/(x^2),x=2 ?

The answer to area 1/x , 1/(x^2),x=2 is ln(2)-1/2

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area 1/x , 1/(x^2),x=2

area

\frac{1}{x}, \frac{1}{x ^{2}}, x = 2

ln (2) - \frac{1}{2}

Decimal Notation

0.19314 \dots

Solution steps

Apply the area formula:

\int_{1}^{2} \frac{1}{x} - \frac{1}{x ^{2}} d x

Solve

\int_{1}^{2} \frac{1}{x} - \frac{1}{x ^{2}} d x : ln (2) - \frac{1}{2}

The area is:

= ln (2) - \frac{1}{2}

\frac{2}{3 s + 5}

\int_{0}^{7} 1 + x^{2} d x

\frac{\partial}{\partial z} (cos (z))

\frac{d}{d x} (\frac{d y}{d x}) + y = cos (x)

\int sec (\frac{x}{3}) - csc (5 x) d x

What is area 1/x , 1/(x^2),x=2 ?
The answer to area 1/x , 1/(x^2),x=2 is ln(2)-1/2