What is the derivative of x^2+3x-4 ?

The derivative of x^2+3x-4 is 2x+3

What is the first derivative of x^2+3x-4 ?

The first derivative of x^2+3x-4 is 2x+3

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derivative of

x^{2} + 3 x - 4

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 2 x + 3 - 0

Simplify

= 2 x + 3

t an g e n t x^{2} - 3 x

x \to 0 lim ((1 + 8 x)^{\frac{7}{x}})

y^{^{'}} = 100 k y - k y^{2}

\int \frac{1}{x - 25} d x

\int \frac{5 x ^{2} + 7 x + 2}{( x ^{2} + 2 ) ( x + 4 )} d x

What is the derivative of x^2+3x-4 ?
The derivative of x^2+3x-4 is 2x+3
What is the first derivative of x^2+3x-4 ?
The first derivative of x^2+3x-4 is 2x+3