What is the limit as x approaches 0 of 0.99^2+1 ?

The limit as x approaches 0 of 0.99^2+1 is 1.9801

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limit as x approaches 0 of 0.99^2+1

x \to 0 lim (0.9 9^{2} + 1)

1.9801

Solution steps

x \to 0 lim (0.9 9^{2} + 1)

x \to a lim c = c

= 0.9 9^{2} + 1

Simplify

= 1.9801

\int \frac{e ^{x} + 9}{( e ^{x} - 3 ) ^{2}} d x

\frac{\partial}{\partial x} (\frac{v ^{2}}{x})

\int - ln (x) e^{- x} d x

f (x) = 4 x e^{x}, at x = 0

\int \frac{x ^{5} - x ^{4} + 4 x ^{3} - 4 x ^{2} + 8 x - 4}{( x ^{2} + 2 ) ^{3}} d x

What is the limit as x approaches 0 of 0.99^2+1 ?
The limit as x approaches 0 of 0.99^2+1 is 1.9801