What is the solution for x((dy)/(dx))+y=3xy^2 ?

The solution for x((dy)/(dx))+y=3xy^2 is y= 1/(x(-3ln(x)+c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x((dy)/(dx))+y=3xy^2

x (\frac{d y}{d x}) + y = 3 x y^{2}

y = \frac{1}{x ( - 3 ln ( x ) + c _{1} )}

Solution steps

x (\frac{d y}{d x}) + y = 3 x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( - 3 ln ( x ) + c _{1} )}

y = \frac{1}{x ( - 3 ln ( x ) + c _{1} )}

\int 7 tan^{3} (x) sec (x) d x

\frac{\partial}{\partial y} (1 + x^{3} + y^{4})

\frac{d x}{d t} = 0.25 - \frac{1}{20} x, x (0) = 0.5

y^{^{''}} + 25 y = 3 sec^{3} (5)

\frac{x}{x ^{2} + y ^{2}}

What is the solution for x((dy)/(dx))+y=3xy^2 ?
The solution for x((dy)/(dx))+y=3xy^2 is y= 1/(x(-3ln(x)+c_{1))}