What is the tangent of f(x)= 9/(x^2),\at x=a ?

The tangent of f(x)= 9/(x^2),\at x=a is y=-(18)/(a^3)x+(27)/(a^2)

tangent of f(x)= 9/(x^2),\at x=a

tangent of

f (x) = \frac{9}{x ^{2}}, at x = a

y = - \frac{18}{a ^{3}} x + \frac{27}{a ^{2}}

Solution steps

Find the tangent point:

(a, \frac{9}{a ^{2}})

Find the slope of

f (x) = \frac{9}{x ^{2}} : \frac{df ( x )}{d x} = - \frac{18}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{18}{a ^{3}}

Find the line with slope m=

- \frac{18}{a ^{3}}

and passing through

(a, \frac{9}{a ^{2}}) : y = - \frac{18}{a ^{3}} x + \frac{27}{a ^{2}}

y = - \frac{18}{a ^{3}} x + \frac{27}{a ^{2}}

n = 2 \sum \infty \frac{1}{n \cdot ( n + 1 )}

d er i v a t i v e f (x) = x^{2} (x^{2} - 8)

\frac{\partial}{\partial y} (e^{3 x} cos (8 y))

\int e^{- t} d t

\int \frac{1 + cos ( x )}{sin ( x )} d x

What is the tangent of f(x)= 9/(x^2),\at x=a ?
The tangent of f(x)= 9/(x^2),\at x=a is y=-(18)/(a^3)x+(27)/(a^2)